यदि `sin^(-1)x=y,` तब-

If sin(x+y) = cos(x-y), then the value of cos^2 x is: यदि sin(x+y) = cos(x-y), तो cos^2 x का मान ज्ञात करें :

If sin^(-1) x + sin^(-1) y=pi/2 , then the value of cos^(-1) x +cos^(-1) y is :

यदि (x-1)/(2) ge 2 , तब x in

sin^-1 x+ sin^-1 y = sin^-1[x 1-y^2 + y 1- x^2]

If x -y = Sin ^(-1) x - Sin ^(-1) y then (dy)/(dx) =

If sin ^ (- 1) x + sin ^ (- 1) y = (pi) / (2), then prove that sin ^ (- 1) x = cos ^ (- 1) y

Draw the graph of following function y = cos ^ (- 1) (cos x) y = sin ^ (- 1) (sin x) y = cos (cos ^ (- 1) x) y = sin (sin ^ (- 1) x)

If (sin x)^(y)=x+y, prove that(dy)/(dx)=(1-(x+y)y cot x)/((x+y)log sin x-1)

If (sin x)^(y)=x+y, prove that (dy)/(dx)=(1-(x+y)y cot x)/((x+y)log sin x-1)