The potential energy U for a force field `vec (F)` is such that `U=-`kxy where K is a constant . Then

The potential energy of a particle in the X-Y plane is given by U=k(x+y) , where 'k' is a constant. Find the amount of work done by the conservative force in moving a particle from (1, 1) to (2, 3).

The potential energy of configuration changes in x and y directions as U=kxy , where k is a positive constant. Find the force acting on the particle of the system as the function of x and y.

The potential energy of configuration changes in x and y directions as U=kxy , where k is a positive constant. Find the force acting on the particle of the system as the function of x and y.

The potential energy of a conservative force field is given by U=ax^(2)-bx where, a and b are positive constants. Find the equilibrium position and discuss whether the equilibrium is stable, unstable or neutral.

The potential energy of a conservative force field is given by U=ax^(2)-bx where, a and b are positive constants. Find the equilibrium position and discuss whether the equilibrium is stable, unstable or neutral.

The potential energy of a particle in a force field is : U= A/r^2-B/r^1 , where A and B are positive constant and r is the centre of the field. For stable equilibrium, the distance of the particle is :

The potential energy for a conservative force system is given by U=ax^(2)-bx . Where a and b are constants find out (a) The expression of force (b) Potential energy at equilibrium.