`sin^2alpha+cos^2(alpha+beta) +2sinalpha sin beta cos(alpha+beta) =` (i)`sin^2(alpha)` (ii)`sin^2(beta)` (iii)`cos^2(alpha)` (iv) `cos^2(beta)`

2sin^(2)beta+4cos(alpha+beta)sin alpha sin beta+cos2(alpha+beta)=

sin ^ (2) alpha + cos ^ (2) (alpha + beta) + 2 sin alpha sin beta cos (alpha + beta) = (i) sin ^ (2) (alpha) (ii) sin ^ (2) (beta ) (iii) cos ^ (2) (alpha) (iv) cos ^ (2) (beta)

Show that: sin^2 alpha + sin^2 beta + 2sinalpha sinbeta cos(alpha+beta)=sin^2 (alpha+beta)

Show that: sin^2 alpha + sin^2 beta + 2sinalpha sinbeta cos(alpha+beta)=sin^2 (alpha+beta)

2 sin ^(2) beta + 4 cos (alpha + beta) sin alpha sin beta + cos 2 (alpha + beta )=

2 sin^(2) beta + 4 cos( alpha+ beta) sin alpha sin beta + cos ( 2 alpha + 2 beta )=

Simplify 2sin^(2)beta+4cos(alpha+beta)sin alpha sin beta+cos2(alpha+beta)

sin ^ (2) alpha + sin ^ (2) (alpha-beta) -2sin alpha cos beta sin (alpha-beta) = sin ^ (2)