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Use the information in the table to calc...

Use the information in the table to calculate the enthalpy of this reaction .
`C_(2)H_(6)(g)+(7)/(2)O_(2)(g)to2CO_(2)(g)+3H_(2)O(l)`
`{:(Reaction ,DeltaH_(f)^(@)KJ.mol^(-1)),(2C(s)+3H_(2)(g)toC_(2)H_(6)(g),-84.7),(2C(s)+O_(2)(g)toCO_(2)(g),-393.5),(H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),-285.8):}`

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The enthalpy of the reaction H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g) is DeltaH_(1) and that of H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l) is DeltaH_(2) . Then

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For the reaction , 2C_(2)H_(6)(g)+7O_(2)(g)rarr4CO_(2)(g)+6H_(2)O(l) , the rate of disappearnce of C_(2)H_(6)(g) :

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Determine Delta U^(@) at 300K for the following reaction using the listed enthalpies of reaction : 4CO(g)+8H_(2)(g)to3CH_(4)(g)+CO_(2)(g)+2H_(2)O(l) C("graphite")+(1)/(2)O_(2)(g)to CO(g), DeltaH_(1)^(@)=-110.5KJ CO(g)(1)/(2)O_(2)(g)toCO_(2)(g), DeltaH_(2)^(@)=-282.9KJ H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l), DeltaH_(3)^(@)=-285.8KJ C("graphite")+2H_(2)(g)to CH_(4)(g), DeltaH_(4)^(@)=-74.8KJ

Determine enthalpy of formation for H_(2)O_(2)(l) , using the listed enthalpies of reaction : N_(2)H_(4)(l)+2H_(2)O_(2)(l)toN_(2)(g)+4H_(2)O(l) , " "Delta_(r)H_(1)^(@)=-818kJ//mol N_(2)H_(4)(l)+O_(2)(g)toN_(2)(g)+2H_(2)O(l) " "Delta_(r)H_(2)^(@)=-622kJ//mol H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)" "Delta_(r)H_(3)^(@)=-285kJ//mol

Determine enthalpy of formation for H_(2)O_(2)(l) , using the listed enthalpies of reaction : N_(2)H_(4)(l)+2H_(2)O_(2)(l)toN_(2)(g)+4H_(2)O(l) , " "Delta_(r)H_(1)^(@)=-818kJ//mol N_(2)H_(4)(l)+O_(2)(g)toN_(2)(g)+2H_(2)O(l) " "Delta_(r)H_(2)^(@)=-622kJ//mol H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)" "Delta_(r)H_(3)^(@)=-285kJ//mol

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