According to the equation
`N_(2)O_(3)(g) + 6H_(2)(g) rArr 2NH_(3)(g) + 3H_(2)O(g)`
how many moles of `NH_(3)(g)` could be formed from the reaction of 0.22 mol of `N_(2)O_(3)`(g) with 0.87 mol of `H_(2)(g)`?

For the reaction : 2 NH_(3)(g) rarr N_(2)(g) + 3 H_(2)(g)

For the reaction, N_2(g)+3H_2(g)rarr2NH_3(g) , which is true:

In the reaction 4NH_(3)+3O_(2(g)) to 2N_(2(g))+6H_(2)O_((g))

For the reaction N_(2)(g) + 3H_(2)(g) rarr 2NH_(2)(g) Which of the following is correct?

For the reaction N_(2)(g) + 3H_(2)(g) rarr 2NH_(2)(g) Which of the following is correct?

Ammonia is produced in accordance with this equation . N_(2)(g) + 3H_(2)(g) rightarrow 2NH_(3)(g) In a particular experiment, 0.25mol of NH_(3) is formed when 0.5 mol of N_(2) is reacted with 0.5 mol of H_(2) . What is the percent yield?

For the reaction N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) , DeltaH = -93.6 KJ mol^(-1) the formation of NH_(3) is expected to increase at :

For the reaction N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) , DeltaH = -93.6 KJ mol^(-1) the formation of NH_(3) is expected to increase at :

In the reaction, 4NH_(3)(g)+5O_(2)(g) rarr 4NO(g)+6H_(2)O(g) , when 1 mole of ammonia and 1 mole of O_(2) are made to react to completion