[" Area bounded by the curves "],[y=x sin x" and "x" -axis betw een "x=0],[" and "x=2 pi" is "]

Area bounded by the curve y=x sin x and x -axis between x=0 and x=2 pi is :

Find the area bounded by the curve y= sin x with x-axis, between x=0 and x=2 pi

[" The area bounded by the curve "],[y=sin^(-1)(sin x)" and the "x" -axis "],[" from "x=0" to "x=4 pi" is equal to "],[" the area bounded by the curve "],[y=cos^(-1)(cos x)" and the x-axis "],[" from "x=-pi" to "x=" a then the "],[" value of "[a]=[.]" G.I.F "]

Area bounded by the curve y=sin x between .x=0 and x=2 pi is

Area bounded by the curve y=max{sin x, cos x} and x -axis, between the lines x=(pi)/(4) and x=2 pi is equal to

The ratio of the areas bounded by the curves y= cos x and y=cos 2x between x=0 , x=(pi)/(3) and x-axis is-

The area bounded by the curve y= sin((x)/(3)), x -axis and lines x=0 and x = 3pi is

The area bounded by the curve y=sin^(2)x-2 sin x and the x-axis, where x in [0, 2pi] , is