The diameter of one drop of water is 0.2 cm. The work done in breaking one drop into 1000 equal droplets will be :-
(surface tension of water `=7xx10^(-2)N//m`)

The diameter of one drop of water is 0.2 cm. The work done in breaking one drop into 1000 droplets will be (Given, S_("water") = 7 xx 10^(-2) Nm^(-1) )

The work done is breaking a water drop of radius 1 cm into 64 equal droplets (Surface tension of water is 0.07 N/m)

Surface tension changes with temperature. Calculate the work done in breaking water drop of radius 1 mm to 1000 droplets. Surface tension of water = 72 x 10^(-3) N/m .

Work done is splitting a drop of water of 1 mm radius into 64 droplets is (surface tension of water =72xx10^(-3)j m^(2))

Work done in splitting a drop of water of 1 mm radius into 10^6 droplets is (Surface tension of water= 72xx10^(-3)J//m^(2) )

Work done in splitting a drop of water of 1 mm radius into 10^(6) droplets is (Surface tension of water= 72xx10^(-3)J//m^(2) )

A big drop of water whose diameter is 0.2 cm, is broken into 27000 small drops of equal volume. Work done in this process will be (surface tension of water is 7xx10^(-2)N//m )

A water drop of radius 10^-2 m is broken into 1000 equal droplets. Calculate the gain in surface energy. Surface tension of water is 0.075Nm^-1

A water drop of radius 10^-2 m is broken into 1000 equal droplets. Calculate the gain in surface energy. Surface tension of water is 0.075Nm^-1

A water drop of radius 10^-2 m is brokenn into 1000 equal droplets. Calculate the gain in surface energy. Surface tension of water ils 0.075Nm^-1