The equilibrium constant for the reaction `Zn(s)+CO_(2)(g)hArrZnO(s)+CO(g)` is

Form the given data of equilibrium constants of the following reactions: CuO(s)+H_(2)(g)hArrCu(s)+H_(2)O(g),K=67 CuO(s)+CO(g)hArrCu(s)+CO_(2)(g),K=490 Calculate the equilibrium constant of the reaction, CO_(2)(g)+H_(2)(g)hArrCu(s)+CO_(2)(g)+H_(2)O(g)

If CoO(s)+H_2(g)hArr Co(s)+H_2O(g), K_1=60 CoO(s)+CO(g)hArrCo(s)+CO_2(g), K_2=180 then the equilibrium constant of the reaction CO_2(g)+H_2(g)hArrCO(g)+H_2O(g) will be

The equilibrium constant K_(c) for the reaction, 2NaHCO_(3)(s)hArrNa_(2)CO_(3)(s)+CO_(2)(g)+H_(2)O(g)

The equilibrium constant K_(c) for the reaction, 2NaHCO_(3)(s)hArrNa_(2)CO_(3)(s)+CO_(2)(g)+H_(2)O(g)

Form the given data of equilibrium constants of the following reactions: CuO(s)+H_(2)(g)hArrCu(s)+H_(2)O(g),K=67 CuO(s)+CO(g)hArrCu(s)+CO_(2)(g),K=490 Calculate the equilibrium constant of the reaction, CO_(2)(g)+H_(2)(g)hArr+CO(g)+H_(2)O(g)

Equilibrium constant for the reaction, CaCO_(3)(s)hArr CaO(s)+CO_(2)(g) at 127^(@)C in one litre container is 8.21xx10^(-3) atm. Moles of CO_(2) at equilibrium is

Equilibrium constant for the reaction, CaCO_(3)(s)hArr CaO(s)+CO_(2)(g) at 127^(@)C in one litre container is 8.21xx10^(-3) atm. Moles of CO_(2) at equilibrium is

The equilibrium constant for the reaction is H_(2)O_((l))+CO_((g)) Leftrightarrow H_(2(g))+CO_(2(g)) is 64. If the rate constant for the forward reaction is 160, the rate constant for the backward reaction is