The Young's modulus of a rubber string 8 cm long and density `1.5kg//m^(3)` is `5xx10^(8)N//m^(2)` is suspended on the ceiling in a room. The increase in length due to its own weight will be-

A thick rope of rubber of density 1.5 (kg)/m^3 Young's modulus 5 xx 10^6 N/M^2 and length 8m is hung from the ceiling of a room . The increase in length due to its own weight is

A rope of rubber of density 1.5xx 10^(3) Kg//m^(3) and Young.s modulus 5 xx 10^(6) N//m^(2) , 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is

A thick rope of rubber of density 1.5 xx 10^(3) kg m^(-3) and Young's modulus 5 xx 10^(6) Nm^(-2) , 8 m in length, when hung from ceiling of a room, the increases in length due to its own weight is

A thick rope of density 1.5 xx 10 ^(3) kg m ^(-3) and Young's modulus 5 xx 10 ^(6) Nm ^(-2), 8 m in length when hung from the ceiling of room the increase in its length due to its own weight is .......... (g = 10 ms ^(-2))

A rubber pipe of density 1.5 xx 10^(3) N//m^(2) and Young's modulus 5 xx 10^(6) N//m^(2) is suspended from the roof. The length of the pipe is 8m. What will be the change in length due to its own weight.

Young's modulus of a rod is (AgL^2)/(2l) for which elongation is lamda due to its own weight when suspended from the ceiling. L is the length of the rod and A is constant, which is:

A rubber string of length 8 m is hanging vertically with one end fixed. If the density of rubber is 1.5 times 10^3 kg.m^-3 and young's modulus is 5 times 10^6 N.m^-2 , then increase of its length due to its own weight will be [ g=10 m.s^-2 ]

The Young's modulus of a material is 2xx10^(11)N//m^(2) and its elastic limit is 1xx10^(8) N//m^(2). For a wire of 1 m length of this material, the maximum elongation achievable is