The position vector of a particle is determined by the expression `vec r = 3t^2 hat i+ 4t^2 hat j + 7 hat k`. The displacement traversed in first `10` seconds is :

If the position vector of a particle is given by vec r= 5t^(2)hat i +7t hat j +4 hat k , then its velocity lies in:

The position vector of a moving particle at 't' sec is given by vec r=3hat i+4t^(2)hat j-t^(3)hat k .Its displacement during an interval of t =1 s to 3 sec is (A) hat j-hat k (B) 3hat i+4hat j-hat k (C) 9hat i+36hat j-27hat k (D) 32hat j-26hat k

If the position vector of a particle is given by vec r =(4 cos 2t) hat j + (6t) hat k m , calculate its acceleration at t=pi//4 second .

The position of a particle is given by vec r= 3.0 t hat i - 2.0 t^2 hat j + 4.0 hat k m , wher (t) in seconds and the coefficients have the proper units for vec r to be in metres. Find the vec v and vec a of the particle ?

The position of a particle is given by vec r= 3.0 t hat i - 2.0 t^2 hat j + 4.0 hat k m , wher (t) in seconds and the coefficients have the proper units for vec r to be in metres. what is the magnitude of the velocity of particle at t=2 sec ?

The position vector of a particle changes with time according to the relation vec(r ) (t) = 15 t^(2) hat(i) + (4 - 20 t^(2)) hat(j) What is the magnitude of the acceleration at t = 1?

Position vector of a particle is expressed as function of time by equation vec(r)=2t^(2)+(3t-1) hat(j) +5hat(k) . Where r is in meters and t is in seconds.