A semi-infinite insulating rod has linear charge density `lambda`. The electric field atthe pointPshown in figure-1.418 is:

A very long charged wire (lying in the xy plane ) which is having a linear charge density lambda is having one of its end at a point P as shown in figure . What is electric field intensity at point Q :

Between two infinitely long wires having linear charge densities lambda and -lambda there are two points A and B shown in the figure. The amount of work done by the electric field moving a point charge q_(0) from A to B is equal to

Consider an infinitely long straight uniformly charged wire with linear charge density lambda To find the electric field at P (located at a distance r from the line of charge), describe an appropriate Gaussian surface.

Between two infinitely long wires having linear charge densities lambda and - lambda , there are two points A and B as shown in the figure. The amount of work done by the electric field in moving a point charge q_(0) from A to B is equal to :

An infinitely long wire with linear charge density +lambda is bent and the two parts are inclined at angle 30^@ as shown in fig, the electric field at point P is :

Two semicircular rings lying in same plane, of uniform linear charge density lambda have radius r and 2r. They are joined using two straight uniformly charged wires of linear charge density lambda and length r as shown in figure. The magnitude of electric field at common centre of semi circular rings is -

Two semicircular rings lying in same plane, of uniform linear charge density lambda have radius r and 2r. They are joined using two straight uniformly charged wires of linear charge density lambda and length r as shown in figure. The magnitude of electric field at common centre of semi circular rings is -