If `(secalpha+tanalpha)(secbeta+tanbeta)(secgamma+tangamma)=tanalphatanbetatangamma`, then `(secalpha-tanalpha)(secbeta-tanbeta)(secgamma-tangamma)=`

If (secalpha+tanalpha)(secbeta+tanbeta)(secgamma+tangamma)=tanalphatanbetatangamma tehn (secalpha-tanalpha)(secbeta-tanbeta)(secgamma-tangamma)=

If tanalpha+tanbeta+tangamma=tanalphatanbetatangamma,then

If tanalpha+tanbeta+tangamma=tanalphatanbetatangamma,then

If (secalpha+tanalpha)(secbeta+tanbeta)(secgamma+tangamma)=(secalpha-tanalpha)(secbeta-tanbeta)(secgamma-tangamma) , then each of the side is equal to

Let alpha,betaa n dgamma be some angles in the first quadrant satisfying tan(alpha+beta)=(15)/8a n dcos e cgamma=(17)/8, then which of the following hold(s) good? alpha+beta+gamma=pi cotalpha+tanbeta+tangamma=tanalphatanbetatangamma tanalpha+tanbeta+tangamma=tanalphatanbetatangamma tanalphatanbeta+tanbetatangamma+tangammatanalpha=1

Let alpha=som^(-1)((36)/(85)),beta=cos^(-1)(4/5)a n dgamma=tan^(-1)(8/(15)) then cotalpha+cotbeta+cotgamma=cotalphacotbetacotgamma tanalphatanbeta+tanbetatangamma+tanalphatangamma=1 tanalpha+tanbeta+tangamma=tanalphatanbetatangamma cotalphacotbeta+cotbetacotgamma+cotalphacotgamma=1

Let alpha=som^(-1)((36)/(85)),beta=cos^(-1)(4/5)a n dgamma=tan^(-1)(8/(15)) then cotalpha+cotbeta+cotgamma=cotalphacotbetacotgamma tanalphatanbeta+tanbetatangamma+tanalphatangamma=1 tanalpha+tanbeta+tangamma=tanalphatanbetatangamma cotalphacotbeta+cotbetacotgamma+cotalphacotgamma=1

Let alpha,betaa n dgamma be some angles in the first quadrant satisfying tan(alpha+beta)=(15)/8a n dcos e cgamma=(17)/8, then which of the following hold(s) good? (a) alpha+beta+gamma=pi (b)cotalpha+tanbeta+tangamma=tanalphatanbetatangamma (c)tanalpha+tanbeta+tangamma=tanalphatanbetatangamma (d)tanalphatanbeta+tanbetatangamma+tangammatanalpha=1

If 2sinalphacosbetasingamma= sinbetasin(alpha+gamma) then tanalpha, tanbeta & tangamma are in

If alpha+beta+gamma=2pi, then- a.tanalpha/2+(tan beta)/2+tangamma/2=tanalpha/2tanbeta/2tangamma/2 b. tanalpha/2+tanbeta/2+tan"(beta/2)tangamma/2=tangamma/2tanalpha/2=1 c.tanalpha/2+t a nbeta/2+tangamma/2=tanalpha/2tanbeta/2tangamma/2 d.tan(alpha/2)tan(beta/2) +tan(gamma/2)tan(beta/2) +tan(gamma/2)tan(alpha/2) =0