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The peak emission from a black body at a...

The peak emission from a black body at a certain temperature occurs at a wavelength of 6200 A. On increasing its temperature, the total radiation emitted is increased 16 times. These radiations are allowed to fall on a metal surface. Photoelectrons emitted by the peak radiation at higher temperature can be bought to rest by applying potential equivalent to the excitation potential corresponding to the transition for the level n=4 to n=2 in the Bohr's hydrogen atom. The work function of the metal is given by `alpha/100 eV` where alpha is the numerical constant. Find the value of alpha.

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Peak emission from a black body at a certain temperature occures at a wavelength lambda. On increasing its temperature , total radiation emitted is increasing 16 times . At the initial temperature when peak radiation from the black body is incident on a metal surface , it does not cause photoemission from surface . After the increasing the peak radiation from black body caused photoemission. to bring these photoelectrons to rest, a potential equivalent to the excitation energy between n=2 to n=3 Bohr levels of hydrogen atom is required. if eork function of metal is 2.24eV , then value of lambda is [hc=12400eV-Å]

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