Home
Class 11
MATHS
If secxcos5x+1=0 , where 0ltxle(pi)/(2)...

If `secxcos5x+1=0 `, where `0ltxle(pi)/(2)`, then find the value of x.

Promotional Banner

Similar Questions

Explore conceptually related problems

Solve : sec x cos 5x+1=0 , where 0ltxle(pi)/(2) .

If sec x cos 5x+1=0 , where 0lt x lt 2pi , then x=

If sec x cos 5x+1=0 , where 0lt x lt 2pi , then x=

If sec x cos 5x+1=0 , where 0lt x lt 2pi , then x=

If sec x cos 5x+1=0 , where 0lt x lt 2pi , then x=

If sec x cos5x+1=0, where 0

Solve that following equations: sec x cos5x+1=0,0

If log_(sinx)(cos x) = (1)/(2) , where x in (0, (pi)/(2)) , then the value of sin x is equal to-

If log_(sinx)(cos x) = (1)/(2) , where x in (0, (pi)/(2)) , then the value of sin x is equal to-

Solve that following equations : sec x cos 5x+1=0, 0 lt x le pi/2 find the value of x