a' moles of `PCl_(5)` are heated in a closed container to equilibrate `PCl_(5) (g) hArr PCl_(3)(g) + Cl_(2) (g) ` at a pressure of p atm . If x moles of `PCl_(5)` dissociate at equilibrium , then

a' moles of PCl_(5) are heated in a closed container to equilibriate PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) at pressure of p atm . If x moles of PCl_(5) dissociate at equilibrium , then

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

Write the Kp expression for PCl_(5(g))hArr PCl_(3(g)) + Cl_(2(g))

For the following equilibrium PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) K_(p) is formed to be equal to K_(x ) . This is attained at

n mole of PCl_(3) and n mole of Cl_(2) are allowed to react at constant temperature T to have a total equilibrium pressure P , as : PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g) If y mole of PCl_(5) are formed at equilibrium , find K_(p) for the given reaction .

n mole of PCl_(3) and n mole of Cl_(2) are allowed to react at constant temperature T to have a total equilibrium pressure P , as : PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g) If y mole of PCl_(5) are formed at equilibrium , find K_(p) for the given reaction .

PCl_(5) dissociation a closed container as : PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_(5) is alpha , the partial pressure of PCl_(3) will be: