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f : C to R : f (z) =|z| is...

`f : C to R : f (z) =|z|` is

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Let C be the set of complex numbers. Prove that the mapping F:C to R given by f(z)=|z|, AA z in C, is neither one-one nor onto.

Let C be the set of complex numbers. Prove that the mapping F:C to R given by f(z)=|z|, AA z in C, is neither one-one nor onto.

Let C be the set of complex numbers. Prove that the mapping F:C to R given by f(z)=|z|, AA z in C, is neither one-one nor onto.

If f: C to R such that f(z) =Re(z) , then f is:

If f: C to R such that f(z) =Re(z) , then f is:

Let C and R denote the set of all complex numbers and all real numbers respectively. Then show that f: C->R given by f(z)=|z| for all z in C is neither one-one nor onto.

Let C and R denote the set of all complex numbers and all real numbers respectively. Then show that f: C->R given by f(z)=|z| for all z in C is neither one-one nor onto.

Let C and R denote the set of all complex numbers and all real numbers respectively. Then show that f: C->R given by f(z)=|z| for all z in C is neither one-one nor onto.