`g(x)=3sin(x-pi/4), 0lt=xlt=(5pi)/4`

f(x)=1+2sinx+3cos^2x ,\ 0lt=xlt=(2pi)/3 is (a)Minimum at x=pi//2 (b) Maximum at x=sin^(-1)(1//sqrt(3)) (c) Minimum at x=pi//6 (d) Maximum at sin^(-1)(1//6)

cos^(-1)((sin x+cos x)/(sqrt(2))),(pi)/(4) lt x lt (5pi)/4

Differentiate (sin x - cos x)^(sin x -cos x) , (-pi)/(4) lt x lt (3pi)/4

Write the range of the function f(x)=sin[x],w h e r e(-pi)/4lt=xlt=pi/4 .

Write the range of the function f(x)=sin[x],w h e r e(-pi)/4lt=xlt=pi/4 .

Simplify each of the following: cos^(-1)(3/5cosx+4/5sinx) , where -(3pi)/4lt=xlt=pi/4

Show that the function f(x) =sin^(4)x+cos^(4)x is increasing in (pi)/(4) lt x lt (3pi)/(8) .

Evaluate the following integral: int_0^9f(x)dx ,\ w h e r e\ f(x){sinx ,\ 0lt=xlt=pi//2 1,pi/2lt=xlt=3e^(x-3),\ 3lt=xlt=9

Solve the equation (sinx+cosx)^(1+sin2x)=2, when 0lt=xlt=pi