Assertion Bamer series lies in the visble region of electromagnetic spectrum.
Reason `(1)/(lambda)=R((1)/(2^(2))-(1)/n^(2))` , where n = 3, 4, 5,.....

Assertion Balmer series lies in the visible region of electromagnetic spectrum. Reason (1)/(lambda)=R((1)/(2^(2))-(1)/n^(2)) , where n = 3, 4, 5,.....

(A) Balmer series lies in the visible region of electromagnetic spectrum (R): (1)/(lambda) = R((1)/(2^(2)) - (1)/(n^(2))) where n = 3,4,5

A: Electromagnetic spectrum has a Balmer series in the visible region. R: (1)/(lambda)=R[(1)/(2^(2))-(1)/(n^(2))] where n=3,4,5,...

Assertion: Balmer series lies in visible region of electromagnetic spectrum. Reason: Balmer means visible, hence series lies in visible region.

Assertion: Lyman series lies in the visible region of electromagnetic spectrum. Reason: This is because Balmer series also lies in visible region.

The wavelength of the various lines in the hydrogen atomic emission spectrum can be related by a mathematical equation: (1)/(lambda) = R ((1)/(n^(2))-(1)/(m^(2))) What is the value of n for the Pfund series of lines?

In case of hydrogen spectrum wave number is given by barv = R_H [(1)/(n_2^2) - 1/(n_2^2)] where n_1 lt n_2

Find the sum of series upto n terms ((2n+1)/(2n-1))+3((2n+1)/(2n-1))^(2)+5((2n+1)/(2n-1))^(3)+

Assertion : Units of Rydberge constant R are m^(-1). Reason : It follows from Bohr's formula [barV = R((1)/(n_1^2) - (1)/(n_2^2))], where the symbole have their usual meaning.