If f(x) is a polynomial of degree 6, which satisfies `lim_(x->0)(1+(f(x)/(x^3)))^(1/x)=e^2` and local minimum at `x=1` and has local maximum at `x=0` and `x = 2`, then the value of `(5/9)^4f(18/5)` is :

f(x) is polynomial function of degree 6, which satisfies ("lim")_(x_vec_0)(1+(f(x))/(x^3))^(1/x)=e^2 and has local maximum at x=1 and local minimum at x=0a n dx=2. then 5f(3) is equal to

f(x) is polynomial function of degree 6, which satisfies ("lim")_(x_vec_0)(1+(f(x))/(x^3))^(1/x)=e^2 and has local maximum at x=1 and local minimum at x=0a n dx=2. then 5f(3) is equal to

Find the polynomial f(x) of degree 6, which satisfies underset(x to 0) ("Limit") (1 + (f(x))/(3))^(1//x) = e^(2) and has local maximum at x = 1 and local minimum at x = 0 & 2.

f(x) is polynomial function of degree 6, which satisfies ("lim")_(xvec0)(1+(f(x))/(x^3))^(1/x)=e^2 and has local maximum at x=1 and local minimum at x=0a n dx=2. Column I, Column II The coefficient of x^6 , p. 0 The coefficient of x^5 , q. 2 The coefficient of x^4 , r. -(12)/5 The coefficient of x^3 , s. 2/3

If f(x) is a polynomial of least degree,such that lim_(x rarr0)(1+(f(x)+x^(2))/(x^(2)))^((1)/(x))=e^(2), then f(2) is

Let f(x) be a polynomial of least degree such that lim_(x rarr0)(1+(x^(4)+f(x^(2)))/(x^(3)))^(1/x)=e^(3), then write the value of f(3)

Show that f(x) = x^5 - 5x^4 + 5x^3 - 1 has a local maximum at x = 1, a local minimum at x = 3 and neither at x = 0

Let f(x) = {(|x-1|+ a",",x le 1),(2x + 3",",x gt 1):} . If f(x) has local minimum at x=1 and a ge 5 then the value of a is