Two particles having de-Broglie wavelengths `lambda_(1) ` and `lambda_(2)`, while moving along mutually perpendicular directions, undergo perfectly inelastic collision. The de-Broglie wavelength `lambda`, of the final particle is

The de-Broglie wavelength lambda

de-Broglie wavelength lambda is

The de Broglie wavelength lambda of a particle

Two particles move at right angle to each other.Their de Broglie wavelengths are lambda_(1) and lambda_(2) respectively.The particles suffer perfectly inelastic collision.The de Broglie wavelength lambda of the final particle is given by :

Two particles move at right angle to each other. Their de Broglie wavelenghts are lambda_(1) and lambda_(2) respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelenght lambda , of the final particle, is given by:

Two particles of de-broglie wavelength lamda_(x) and lamda_(y) are moving in opposite direction. Find debroglie wavelength after perfectly inelastic collision:

Two particles of de-broglie wavelength lamda_(x) and lamda_(y) are moving in opposite direction. Find debroglie wavelength after perfectly inelastic collision:

The de Broglie wavelength (lambda) associated with a material particle is_____.