" 2) "tan0times cot0=?

Value of (3+cot80^0cot20^0)/(cot80^0+cot20^0) is equal to (a) cot20^0 (b) tan50^0 (c) cot50^0 (d) cotsqrt(20^0)

Value of (3+cot80^0cot20^0)/(cot80^0+cot20^0) is equal to (a) cot20^0 (b) tan50^0 (c) cot50^0 (d) cotsqrt(20^0)

Value of (3+cot80^0cot20^0)/(cot80^0+cot20^0) is equal to (a) cot20^0 (b) tan50^0 (c) cot50^0 (d) cotsqrt(20^0)

Solve the equation 2 tan theta - cot theta + 1 = 0

If in a ABC,tan A+tan B+tan C=0 then cot A cot B cot C=6b.1c*(1)/(6)d .none of these

Show that tan 75^0 + cot 75^0 = 4

Let theta = (0,(pi)/(4)) and t_(0) = (tan theta)^(tan theta), t_(2) = (tan theta)^(cot theta), t_(3) = (cot theta)^(tan theta) .t_(4) = (cot theta)^(cot theta) then

Evaluate: (sec theta csc(90^(0)-theta)-tan theta cot(90^(0)-theta)+sin^(2)55^(0)+sin^(2)35^(@))/(tan10^(0)tan20^(0)tan60^(@)tan70^(0)tan80^(0))

Solve : (0^@le thetale90^@) : tan theta +cot theta=2