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यदि bar(u),bar(v),bar(w) असमतलीय सदिश हो...

यदि `bar(u),bar(v),bar(w)` असमतलीय सदिश हों तथा p, q वास्तविक संख्याएँ हों तब
`[3bar(u),p bar(v),p bar(w)]-[p bar(v),bar(w),q bar(u)]-[2bar(w),qbar(v),q bar(u)]=0` निम्नलिखित के लिए सत्य है :

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