Find the GCD of the fractions `(3)/(5),(4)/(7)and (7)/(10)`. The following are the steps involved in solving the above problem. Arrange them in the sequential order.
(A) We have, the GCD of fractins `=("GCD of numerators")/("LCM of denominators")`
(B) The rquired GCD `=(1)/(70)`
(C) The GCD of `3,4,7, is 1,`. The LCM of `5,7 and 10 is 70`.

Find the GCD of the following : 3a^(2) , 5b^(3) , 7c^(4)

Find the L.C.M of 4/5, 2/3 and 5/7

Find the GCD for the following : 3abc, 5xyz, 7pqr

If A = (3,-4) , B= (7,0) and C = (14 , -7) are the three consecutive vertices of a parallelogram ABCD , then find the slope of the diagonal BD . The following are the steps involved in solving the above problem . Arrange them is sequential order (A) ((x + 7)/(2) , (y + 0)/(2)) = ((3 + 14)/(2) , (-4-7)/(2)) . (B) The slope of BD = (-11-0)/(10-7) = (-11)/(3) . (C) (x+7)/(2) = (17)/(2) and (y+0)/(2) - (-11)/(2) implies x = 10 , y = -11 therefore D = (10 , -11) . (D) Let the fourth vertex be D(x , y) . we know that the diagonals of a parallelogram bisect each other .