If `u=inte^(ax)cos bx dx` and `v=int e^(ax)sinbx dx`, show that,
`"tan"^(-1)(v)/(u)+"tan"^(-1)(b)/(a)=bx`.

inte^(ax)sin(bx+c)dx

int e^(ax)2^(bx)dx

If u=inte^(ax)cos bx dx and v=int e^(ax)sinbx dx , show that, (a^(2)+b^(2))(u^(2)+v^(2))=e^(2ax)

int e^(ax)cos(bx+c)dx

int(e^(b)cos bx)dx=?

If u=inte^(ax)sin " bx dx" and v=int^(e^(ax))cos " bx dx" ,then tan^(-1)((u)/(v))+tan^(-1)((b)/(a)) equals

If u=inte^(ax)sin " bx dx" and v=int(e^(ax))cos " bx dx" ,then tan^(-1)((u)/(v))+tan^(-1)((b)/(a)) equals

Method of integration by parts : If u=inte^(ax)cos bx dx and v= int e^(ax) sin bx dx then (a^(2)+b^(2))(u^(2)+v^(2))=....

int (e ^ (ax) + sin bx) dx