The mass of moon is about 0.012 times that of earth and its diameter is about 0.25 times that of earth .The value of G on the moon will be

An astronaut on the moon measures the acceleration due to gravity to be 1.7 ms^(-2) . He known that the radius of the moon is about 0.27 times that of the earth . Find the ratio of the mass of the earth to that of the moon , if the value of g on the earth's surface is 9.8 ms^(-2) .

Given that the mass of the earth is 81.5 times the mass of the moon and the diameter of the moon is 0.27 times that of the earth . Calculate the value of acceleration due to gravity at the surface of the moon . Given 'g' on the earth = 9.8 ms^(-2)

If the mass of the earth is 100 times that of the moon and its diameter 5 times that of moon, compare the weight of a body on the surface of the moon with its weight on the surface of the earth.

If the accelaeration due to gravity g at the earth's surface is 9.8 ms^-2 and mass of earth is 80 times that of moon and radius of earth 4 times that of moon , the value of g at the moon's surface will be

The mass of earth is 80 times that of moon. Their diameters are 12800 km and 3200 km respectively. The value of g on moon will be, if its value on earth is 980cm//s^(2)

The mass of the earth is 81 times that of the moon and the radius of the earth is 3.5 times that of the moon. The ratio of the escape velocity on the surface of earth to that on the surface of moon will be

The mass of the earth is 81 times that of the moon and the radius of the earth is 3.5 times that of the moon. The ratio of the acceleration due to gravity at the surface of the moon to that at the surface of the earth is

If the mass of the earth is 80 times of that of moon and its diameter is double that of moon and g on earth is 98m//sec^2 ,then the value of g on moon is

The radius of the moon is 1//4 th the radius of the earth and its mass is 1//80 th the mass of the earth. Calculate the value of g on the surface of the moon.