A moving electron has `4.55 xx 10^(-25)` joules of kinetic energy. Calculate its wavelength (mass` = 9.1 xx 10^(-31)` kg and `h = 6.626 xx 10^(-34) kg m^2 s^(-1)` ).

Explanation

Here we given
kinetic energy `1/2 mv^2 = 4.55 xx 10^(-25) J`
`m = 9.1 xx 10^(-31) kg `
`h = 6.626 xx 10^(-34) kg m^2 s^(-1)`
` therefore 1/2 xx (9.1 xx 10^(-31) ) v^2 = 4.55 xx 10^(-25)`
` v^2 = (4.55 xx 10^(-25) xx 2)/(9.1 xx 10^(-31)) = 10^6`
` v = 10^3 ms^(-1)`
` therefore lamda = (h)/(mv) = (6.626 xx 10^(-34))/((9.1 xx 10^(-31) ) xx 10^3)`
` = 7.25 xx 10^(-7) m`