`H_(3)PO_(3)` is diprotic (or dibasic). Why?

Give reasons for the following : (i) (CH_(3))_(3)P=O exists but (CH_(3))_(3)N=O does not. (ii) Oxygen has less electron gain enthalpy with negative sign than sulphur. (iii) H_(3)PO_(2) is a stronger reducing agent than H_(3)PO_(3) .

Is the given relation correct for an aqueous dilute solution of K_(3)PO_(4) if its degree of dissociation is alpha ?

Between H_(2)S and H_(2)O, H_(2)O is more polar. Why?

In the reaction C_(6)H_(5)NH_(2)underset(0^(@)C)overset(HONO)rarrXoverset(H_(3)PO_(3))rarrY the product y is

Why is boric acid ( H_(3) BO_(3)) a monobasic acid ?

Of PH_(3) and H_(2)S which is more acidic and why?