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The end product of decay of ""(90)Th^(23...

The end product of decay of `""_(90)Th^(232)` is `""_(82)Pb^(208)` . The number of `alpha` and `beta` particles emitted are respectively

Text Solution

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Let a and b be the number of `alpha beta` particles emitted during the change comparing the mass numbers
232 +208 +4a+b x0
4a=232-208
a=6
number of `alpha` paritcle emitted =6
number of `beta` particles emitted =4
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