On neutron bombardment fragmentation of U-235 occurs according to the equation
`92^(U^(235)) + 0^(n^(1)) rarr 42^(Mo^(95)) + 57^(La^(139)) + x_(-1)^(e^(0)) + y_(0)^(n^(1))` Calculate the values of x and y.

If lim_(h rarr 0) (1 + (a)/(x) + (b)/(x^(2)))^(2x) = e^(2) , then the values of a and b, are :

Consider the reaction: ""_(92)^(238)U+""_(0)^(1)nto""_(92)^(239)Mto""_(93)^(239)Np+""_(-1)^(0)e M is :

A thermal neutron strikes U_(92)^(235) nucleus to produce fission. The nuclear reaction is as given below : n_(0)^(1) + U_(92)^(235) to Ba_(56)^(141) + Kr_(36)^(92) +3n_(0)^(1) + E Calculate the energy released in MeV. Hence calculate the total energy released in the fission of 1 Kg of U_(92)^(235) . Given mass of U_(92)^(235) = 235.043933 amu Mass of neutron n_(0)^(1) =1.008665 amu Mass of Ba_(56)^(141)=140.917700 amu Mass of Kr_(36)^(92)=91.895400 amu

If m, n are the roots of the equations x^(2) -2x+ 3 =0 . Find the value of (1)/(m^(2)) +(1)/( n^(2))

lim_(x rarr 0) (2^(x)-1)/((1+x) ^ (1/2) -1) =

If m and n are the roots of the equations x^(2) - 6x+ 2 =0 then the value of (1)/(m) + (1)/( n) is :

The solution of the differential equation : (1+y^2)+(x-e^(tan^(-1)y))(dy)/(dx)=0 is :

The general solution of the differential equations : x(1+y^2)dx+y(1+x^2)dy=0 is :

If (1+x+x^(2))^(n) = a_(0)+a_(1) x+a_(2) x^(2)+.. .+a_(2 n) x^(2 n) then the value of a_(0)+a_(3)+a_(6)+.. . . is