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The electron energy of hydrogen atom in ...

The electron energy of hydrogen atom in the ground state works out to be ` - 2.18 xx 10^(-18)` J per atom. Calculate what will happen to the position of the electron in this atom if an energy of `1.938 xx 10^(-18)`J is supplied to the each hydrogen atom.

Text Solution

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Energy of H atom in the ground state `= -2.18 xx 10^(-18) J "atom"^(-1)`
Energy added =` 1.938 xx 10^(-18) J "atom"^(-1)`
Energy of electron in the excited state `= (-2.18 + 1.938) xx 10^(-18) J "atom"^(-1) = -0.242 xx 10^(-18) J "atom"^(-1)`
` therefore - 0.242 xx 10^(-18) J "atom"^(-1) = (-2.18 xx 10^(-18) J "atom"^(-1))/(n^2)`
`n^2 = (-2.18 xx 10^(-18) J "atom"^(-1) )/(-0.242 xx 10^(-18) J "atom"^(-1) ) = 9 , n = 3`
Hence electron will get excited to third shell.
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