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Determine the average life of U^(238) ha...

Determine the average life of `U^(238)` having `t^(1//2)` = 140 days.

Text Solution

Verified by Experts

`t^(1//2)=(0.693)/(lambda)`
`tau=(t^(1//2))/(0.693)`
=202.02 days
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NCERT TAMIL-NUCLEAR CHEMISTRY-SELF EVALUATION
  1. Determine the average life of U^(238) having t^(1//2) = 140 days.

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  2. The phenomenon of radioactivity was discovered by

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  3. The most penetrating radiations are

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  4. In the nuclear reaction, 92^(X^(232))rarr 89^(Y^(220)), the number of ...

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  5. Which one of the following particles is used to bombard 13^(Al^(27)) t...

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  6. Radioactivity is due to

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  7. In the nuclear reaction, 92^(X^(232))rarr 89^(Y^(220)), the number of ...

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  8. 92^(U^(235)) nucleus absorbs a neutron and disintegrates into 54^(Xe^(...

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  9. Assertion: The ionision power of beta-particle is less compared to alp...

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  10. Which of the following is used as a moderator and coolant in nuclear r...

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  11. What is half life period.

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  12. Write two difference between chemical reaction and nuclear reaction.

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  13. Why do you mean be Q value of nuclear reaction ?

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  14. What are the types of nuclear reaction. Give example for each type.

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  15. What is Radio carbon dating?

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  16. What is binding energy of a nucleus? Give its expression.

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  17. What is nuclear fusion? How do nuclear fusion reactions differ from fi...

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  18. What is thermo chemical reactions?

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  19. Explain the uses of radio isotopes in medicine field.

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  20. How many alpha and beta particles will be emitted by an element 84^(A^...

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  21. Calculate the decay constant for Ag^(108) if its half life is 2.31 min...

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