A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of the parabola `y^2 = 16x` `0leyle6` at the point art `F(x_0,y_0)`. The tangent to the parabola at `F(X_0,Y_0)` intersects the y-axis at `G(0,y)`. The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum P) m= Q) = Maximum area of `triangle EFG` is (R) `y_0=` (S) `y_1=`

line L:y=mx+3 meets y–axis at E(0, 3) and the are of the parabola y^(2)=16x, 0leyle6 at the point F(x_(0),y_(0)) . The tangent to the parabola at F(x_(0),y_(0)) intersects the y-axis at G(0,y_(1)) . The slope m of the L is chosen such that the area of the triangle EFG has a local maximum. Match List I with List II and select the correct answer using the code given below the lists :

A line L:y=mx+3 meets y-axis at E(0,3) and the arc of the parabola y 2 =16x,0≤y≤6 at the point F(x 0 ​ ,y 0 ​ ). The tangent to the parabola at F(x 0 ​ ,y 0 ​ ) intersects the y-axis at G(0,y 1 ​ ). The slope m of the line L is chosen such that the area of the △EFG has a local maximum. Match List 1 with List 2 List 1 List 2 A. m= 1. 2 1 ​ B. Maximum area of ΔEFG is 2. 4 C. y 0 ​ = 3. 2 D. y 1 ​ = 4. 1

Axis of the parabola y^2-16x+6y+89=0 , is:

The axis of the parabola y^(2)+4x+4y-3=0 is

Axis of the parabola x^2 - 3y - 6x + 6 = 0 is

Tangents are drawn to the parabola y^2=4a x at the point where the line l x+m y+n=0 meets this parabola. Find the point of intersection of these tangents.

Tangents are drawn to the parabola y^2=4a x at the point where the line l x+m y+n=0 meets this parabola. Find the point of intersection of these tangents.

Tangents are drawn to the parabola y^2=4a x at the point where the line l x+m y+n=0 meets this parabola. Find the point of intersection of these tangents.

Tangents are drawn to the parabola y^2=4a x at the point where the line l x+m y+n=0 meets this parabola. Find the point of intersection of these tangents.