दिखाइए कि xy=log y +c का हल (dy)/(dx)...

दिखाइए कि `xy=log y +c` का हल `(dy)/(dx)=(y^(2))/(1-xy)(xy ne 1)` है ।

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(dy)/(dx)=(y^(2)-x)/(xy+y)

xy(dy)/(dx)=y+2

(dy)/(dx)=(xy+y)/(xy+x)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

(dy)/(dx)+(xy+y)/(xy+x)=0

Solve (dy)/(dx) =(y^(2)-2xy)/(x^(2)-xy)

If xy =log (xy) ,then (dy)/(dx)=

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