y=sin^(-1)x" in powers of "x

Draw the graph of y = sin^(-1)2x" and "y=sin^(-1)(x//2)" and compare with " y = sin^(-1)x .

Draw the graph of y = sin^(-1)2x" and "y=sin^(-1)(x//2)" and compare with " y = sin^(-1)x .

If x -y = Sin ^(-1) x - Sin ^(-1) y then (dy)/(dx) =

Draw the graph of following function y = cos ^ (- 1) (cos x) y = sin ^ (- 1) (sin x) y = cos (cos ^ (- 1) x) y = sin (sin ^ (- 1) x)

If sin ^ (- 1) x + sin ^ (- 1) y = (pi) / (2), then prove that sin ^ (- 1) x = cos ^ (- 1) y

The area of the region, bounded by the curves y=sin^(-1)x+x(1-x) and y=sin^(-1)x-x(1-x) in the first quadrant is-

Find the area bounded by the curves y=(sin^(-1)(sin x)+cos^(-1)(cos x)) and y=(sin^(-1)(sin x)+cos^(-1)(cos x))^(2) for 0<=x<=2 pi

If sin^(-1) x + sin^(-1) y = pi/2 , prove that x sqrt(1-y^2) + y sqrt(1-x^2) =1 .

If sin^(-1) x + sin^(-1) y = pi/2 , prove that x sqrt(1-x^2) + y sqrt(1-y^2) =1 .