The line `bx + ay = 3ab` cuts the coordinate axes at A and B, then centroid of triangle `DeltaOAB` is

If the plane 3x+4y-3z+2=0 cuts the coordinate axes at A, B, C, then the centroid of the triangle ABC is

A straight line meets the coordinates axes at A and B, so that the centroid of the triangle OAB is (1, 2). Then the equation of the line AB is

The plane ax + by + cz = 1 meets the coordinate axes in A, B, C. The centroid of the triangle is :

The plane ax+by+cz=1 meets the coordinate axes in A,B,C. The centroid of Delta ABC is

The equation of the plane, which cuts the coordinate axes at A,B and C such that the centroid of Delta ABC is at the point (-2,-1,-4),is

A circle of radius 'r' passes through the origin O and cuts the axes at A and B,Locus of the centroid of triangle OAB is

A circle of radius 'R' passes through the origin O and cuts the axes at A and B,Locus of the centroid of triangle OAB is