1 gram of ice is mixed with 1 gram of steam. At thermal equilibrium, the temperature of the mixture is

One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of the mixture is

1 g of ice is mixed with 1 g of steam. At thermal equilibrium, the temperature of the mixture is¬

1 g of ice at 0^@C is mixed with 1 g of steam at 100^@C . After thermal equilibrium is achieved, the temperature of the mixture is

1 g of ice at 0^@C is mixed with 1 g of steam at 100^@C . After thermal equilibrium is achieved, the temperature of the mixture is

. 540 gram of ice at 0^@C is mixed with 540 gram of water at 80^@C . The final temperature' of the mixture is

60 g of ice at 0^@C is mixed with 60 g of steam at 100^@C . At thermal equilibrium, the mixture contains (Latent heat of steam and ice are 540 g^-1 and 80 cal g^-1 respectively, specific heat of water = 1cal g^-1^@C^-1 )