" ) "sin2x

If the maximum and minimum values of the determinant |(1 + sin^(2)x,cos^(2) x,sin 2x),(sin^(2) x,1 + cos^(2) x,sin 2x),(sin^(2) x,cos^(2) x,1 + sin 2x)| are alpha and beta , then

If the maximum and minimum values of the determinant |(1 + sin^(2)x,cos^(2) x,sin 2x),(sin^(2) x,1 + cos^(2) x,sin 2x),(sin^(2) x,cos^(2) x,1 + sin 2x)| are alpha and beta , then

If the maximum and minimum values of the determinant |(1 + sin^(2)x,cos^(2) x,sin 2x),(sin^(2) x,1 + cos^(2) x,sin 2x),(sin^(2) x,cos^(2) x,1 + sin 2x)| are alpha and beta , then

Range of f(x) = (sin^2x + sin x -1)/(sin^2x - sin x + 2)

Let f(x)=|[1+sin ^2 x, cos ^2 x , 4 sin 2 x],[ sin ^2 x ,1+cos ^2 x , 4 sin 2 x],[ sin ^2 x , cos ^2 x , 1+4 sin 2 x]| , the maximum value of f(x) is

" If determinant "|[cos^(2)x,sin^(2)x,cos^(2)x],[sin^(2)x,cos^(2)x,sin^(2)x],[cos^(2)x,sin^(2)x,-cos^(2)x]|" is expanded as a function of "sin^(2)x" ,then the absolute value of constant term in expansion of function "

Prove that sin x + sin 2x + sin 3x = sin 2x (1 + 2 cos x )

int e^(sin^(2)x). sin 2x dx =

Compute the following: [[cos^2x, sin^2x],[sin^2x, cos^2x]]+[[sin^2x, cos^2x],[cos^2x, sin^2x]]