`log_10 {log10x} = 1 `then `x`

if x+log_10 (1+2^x)=xlog_10 5+log_10 6 then x

if x+log_10 (1+2^x)=xlog_10 5+log_10 6 then x

Given that log_10 2 =x, log_10 3 =y then log_10 1.2=

If log_(10) x+log_(10) y= 3 and log_(10) x-log_(10) y=1, then x and y are respectively a. 10 and 100 b. 100 and 10 c. 1000 and 100 d. 100 and 1000

if x+log_(10)(1+2^(x))=x log_(10)5+log_(10)6 then x

Find the domain of definition of the function f(x) = log_10 log_10 log_10 { (x + 1)(x - 2)} .

If x + log_(10) ( 1 + 2^(x)) = x log_(10) 5 + log_(10)6, then the value of x is