If `theta` is the acute angle butween the pair of lines represented by `3x^2-8xy + 4y^2=0` then `(2 cos theta + 3 sin theta)/(4 sin theta + 5 cos theta)` is

If theta is the acute angle between the pair of the lines x^(2)+3xy4y^(2)=0 then sin theta=

If theta is the acute angle between the pair of lines 5x^2-8xy-y^2=0 then find cos theta

4 sin 5 theta cos 3 theta sin 2 theta

If theta is the acute between the pair of lines x^(2)+3xy-4y^(2)=0 then sin theta=

If theta is the parameter, then the family of lines represented by (2cos theta+3 sin theta)x+(3 cos theta-5sin theta)y-(5cos theta-7sin theta)=0 are concurrent at the point

Solve : 3-2 cos theta -4 sin theta - cos 2theta+sin 2theta=0 .

Solve : 3-2 cos theta -4 sin theta - cos 2theta+sin 2theta=0 .