The kinetic energy of a molecule of hydrogen at `0^(@) is 5.64 xx 10^(-21) J`. Calculate Avogadro's number. Take ` R = 8.31 xx J "mole"^(-1) K^(-1)`

The kinetic energy of a molecule of oxygen at 0^(@)C is 5.64 xx 10^(-21) J . Calculate Avogadro's number. Given R = 8.31 J "mol^(-1)K^(-1) .

Kinetic energy of oxygen molecule at 0^(@) C is 9.4 xx 10^(-21) j . Calculate Avogadro's number, when R = 8.31 J "mole"^(-1) K^(-1) .

Find the value of Avogadro number. Given the mean value of kinetic energy of a molecule of hydrogen at 273K is 5.64xx 10^(-21) J and R = 8.31 J m o l^(-1) K^(-1) .

The kinetic energy of two moles of N_(2) at 27^(@) C is (R = 8.314 J K^(-1) mol^(-1))

The kinetic energy of two moles of N_(2) at 27^(@) C is (R = 8.314 J K^(-1) mol^(-1))

At 0^(@)C the kinetic energy of 1O_(2) molecule is 5.62xx10^(-14) erg. Determine avogadro's number.

At what temperature the kinetic energy of a molecule will be equal to 2.8 xx 10^(-20) J ? Boltzmann constant (k_(B)) = 1.4 xx 10^(-23) J "molecule"^(-1)K^(-1)

The kinetic energy in J of 1 mole of N_2 at 27^@ C is (R= 8.314 mol^(-1) k^(-1))

The average kinetic energy of a gas molecule at 0^(@)C is 5.621xx10^(-21) J . Calculate Boltzmann costant. Also calculate the number of molecules present in one mole of the gas.