[" Let "alpha in(0,pi/2)" be fixed.If the integral "],[int(tan x+tan alpha)/(tan x-tan alpha)dx=A(x)cos2 alpha+B(x]

Let alpha in (0, pi/2) be fixed. If the integral int(tan x + tan alpha)/(tan x - tan alpha)dx = A(x)cos 2 alpha+B(x) sin 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

Let alpha in (0, pi//2) be fixed. If the integral int("tan x" + "tan" alpha)/("tan x" - "tan" alpha)dx = A(x)"cos 2 alpha+B(x) "sin" 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

Let alpha in (0, pi//2) be fixed. If the integral int("tan x" + "tan" alpha)/("tan x" - "tan" alpha)dx = A(x)"cos 2 alpha+B(x) "sin" 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

int{1+tan x*tan(x+alpha)}dx=

(x tan alpha+y cot alpha)(x cot alpha+y tan alpha)-4xy cos^(2)2 alpha=

int tan(x-alpha).tan(x+alpha).tan 2x dx is equal to

int tan(x-alpha).tan(x+alpha).tan 2x dx is equal to

If alpha=(2 pi)/(7), then tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha

If alpha=(2 pi)/(7) then tan alpha tan^(7)2 alpha+tan2 alpha tan4 alpha+tan2 alpha tan4 alpha=