In the dissociation of `N_(2)O_(4)` into `NO_(2). (1+x)` values with the vapour densities ratio `((D)/(d))` is given by `:`

In the dissociation of N_(2)O_(4) into NO_(2), (1+ alpha) values with the vapour densities ratio ((D)/(d)) is given by: [ alpha degree of dissociation, D-vapour density before dissociation, d-vapour density after dissociation]

In the dissociation of N_(2)O_(4) into NO_(2), (1+ alpha) values with the vapour densities ratio ((D)/(d)) is given by: [ alpha degree of dissociation, D-vapour density before dissociation, d-vapour density after dissociation]

A mixture contains N_(2)O_(4) and NO_(2) in the ratio 2:1 by volume. Calculate the vapour density of the mixture?

A mixture contains N_(2)O_(4) and NO_(2) in the ratio 2:1 by volume. The vapour density of the mixture is:

A mixture contains N_(2)O_(4) and NO_(2) in the ratio 2:1 by volume. The vapour density of the mixture is:

If air contains N_(2) and O_(2) in volume ratio 4 : 1 , the average vapour density of air is:

For the dissociation of NH_(3)(g) as 2NH_(3)(g)iffN_(2)(g)+3H_(2)(g) , the variation of (1 + alpha) against ((D)/(d)) is represented as : (Given : D = initial vapour density of PCl_(5) , d = Vapour density of mixture at equilibriu,):