A particle of mass m is rotated in a circular path of radius r under the influence of a force `F=-k/(r^2)`, where k is a constant. Find the total energy of the particle.

A particle of mass m is revolving in a horizontal circle of radius r under a centripetal force k//r^(2) where k is a constant. What is the total energy of the particle ?

A particle of mass m is moving in a horizontal circle of radius r under centripetal force given by (- k//r^(2)) where k is a constant . Then the total energy of the particle is _________ .

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A particle of mass M moves with constant speed along a circular path of radius r under the action of a force F. Its speed is

A particle of mass M moves with constant speed along a circular path of radius r under the action of a force F. Its speed is

A particle of mass m is moving is a horizontal circle of radius x under a centripetal force equal to - (kv^(2)) where it is constant The total energy of the particle is