The trajectory of a projectile is given by `y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta)`. This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing.
In the previous problem, what should be the corresponding projection angle.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. A tower is at a distance of 5m from a man who can throw a stone with a maximum speed of 10m//s . What is the maximum height that the man can hit on this tower.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. A tower is at a distance of 5m from a man who can throw a stone with a maximum speed of 10m//s . What is the maximum height that the man can hit on this tower.

The angle of projection for a projectile to cover maximum range is :

The maximum range of projectile is 2/ √ 3 times actual range. What isthe angle of projection for the actual range ?

The maximum range of projectile is 2/sqrt3 times actual range. What isthe angle of projection for the actual range ?

The maximum range of a projectile is 2/sqrt3 times its actual range. What is the angle of projection for the actual range?