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y=x^3y^4=(x+y)^7...

`y=x^3y^4=(x+y)^7`

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x^(3)y^(4)=(x+y)^(7) ,find (dy)/(dx)

x^(3)y^(4)=(x-y)^(7) Differentiate it and

given x=(sqrt(7)+sqrt(3))/(sqrt(7)-sqrt(3)),y=(sqrt(7)-sqrt(3))/(sqrt(7)+sqrt(3)) find the value of x^(4)+y^(4)+(x+y)^(4)

y = x ^ (3) y ^ (4) = (x + y) ^ (7)

Simplify: (3x+2y)(4x+3y)-(2x-y)(7x-3y)

Find the greatest value of x^3y^4 if 2x + 3y = 7 and x>=0,y>=0 .

Find the greatest value of x^3y^4 if 2x + 3y = 7 and x>=0,y>=0 .

Find the greatest value of x^3y^4 if 2x + 3y = 7 and x>=0,y>=0 .

Find the greatest value of x^3y^4 if 2x + 3y = 7 and x>=0,y>=0 .

x-y=3 2x+3y+4z=17 y+2z=7