A 60 kg weight is dragged on a horizontal surface by a rope upto 2 metres. If coefficient of friction is `mu=0.5` the angle of rope with the surface is `60^(@)`and `g=9.8m//sec^(2),` then work done is

A force of 10N is acting on a block of 20kg on horizontal surface with coefficient of friction mu=0.2 . Calculate the work done by the force.

A force of 10N is acting on a block of 20kg on horizontal surface with coefficient of friction mu=0.2 . Calculate the work done by the force.

A block of mass 50 kg slides over a horizontal distance of 1m. If the coefficient of friction between their surface is 0.2, then work done against friction is (take g = 9.8 m//s^(2) ) :

A block of mass 50 kg slides over a horizontal distance of 1m. If the coefficient of friction between their surface is 0.2, then work done against friction is (take g = 9.8 m//s^(2) ) :

A body of mass 2 kg is kept on a rough horizontal surface as shown in the figure. If coefficient of friction is 0.5, find the work done by frictional force in the interval t=0 to t=5 sec

The minimum force required to keep a block sliding with a uniform velocity along a horizontal surface, is 49 N, Find the coefficient of Kinetic friction if the mass of the block is 8 kg and (g = 9.8m//s^2) .

A force of 98 N is just able to move a block of mass 20 kg on a rough horizontal surface. Calculate the coefficient of friction and the angle of friction (g = 9.8 ms ^(-2)).

A block of mass 1 kg slides down on a rough inclined plane of inclination 60^(@) starting from its top. If the coefficient of kinetic friction is 0.5 and length of the plane is 1 m , then work done against friction is (Take g=9.8m//s^(2) )

A block of mass 5kg is on a rough horizontal surface and is at rest. Now a force of 24 N is imparted to it with negligible impulse. If the coefficient of kinetic friction is 0.4 and g=9.8m//s^(2) , then the acceleration of the block is