Home
Class 12
MATHS
The equation of the diameter of the circ...

The equation of the diameter of the circle `3(x^(2)+y^(2))-2x+6x-9-0` which is perpendicular to the line 2x+3y=12 is

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the diameter of the circle 3(x^(2)+y^(2))-2x+6y-9=0 which is perpendicular to the line 2x+3y=12 is

The equation of the diameter of the circle x^(2) + y^(2) -4x-6y +3 = 0 that is perpendicular 2x + 5y-6 = 0 is

The equation of a diameter of the circle x^2 + y^2 = 2ay that is perpendicular to the straight line x + 2y = 4 is :

find the equations of tangents to the circle x^2+y^2-4x-6y-12=0 which are perpendicular to the line 4x+3y=7

The equations of the tangents to the hyperbola 2x^(2) -3y^(2) =6 which are perpendicular to the line x-2y+5 =0 are

The equation of the diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 which passes through origin is

The equation of the tangents to the circle x ^(2) + y ^(2) - 6x + 4y - 12 =0 which are parallel to the line 4x + 3y + 5=0 are :

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)+6x+2y=0