If x is real, prove that `(x)/(x^(2)-5x+9)` lies between 1 and `(-1)/(11)`.

(x)/(x^(2)-5x+9)<=1

If x is real number, then x/(x^(2)-5x+9) must lie between

If x is real,then x/(x^(2)-5x+9) lies between -1 and -1/11 b.1 and -1/11 c. 1and1/11d.none of these

If x is real, then x//(x^2-5x+9) =y lies between -1a n d-1//11 b. 1a n d-1//11 c. 1a n d1//11 d. none of these

If x is real, then x//(x^2-5x+9) lies between -1a n d-1//11 b. 1a n d-1//11 c. 1a n d1//11 d. none of these

If x is real, then x//(x^2-5x+9) lies between -1a n d-1//11 b. 1a n d-1//11 c. 1a n d1//11 d. none of these

If x is real, then x//(x^2-5x+9) lies between a. -1a n d-1//11 b. 1a n d-1//11 c. 1a n d1//11 d. none of these

if x is real,show that (x)/(x^(2)-5x+9) always lies in the interval [-(1)/(11),1]

If x is real, show that the value of x/(x^2-5x+9) always lie between 1 and (-1/11)