If Tn =sin^n theta+cos^n theta, then (T6...

If `T_n =sin^n theta+cos^n theta,` then `(T_6-T_4)/T_6 =m` holds for values of `m` satisfying (A) `m in [-1, 1/3]` (B) `m in [0, 1/3]` (C) `m in [-1,0]` (D) `m in [-1, - 1/2]`

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