Explain why :
(i) The three electrons present in 2p sub-shell of nitrogen remain unpaired.
(ii) In potassium , the `19^(th)` electron enters 4s sub-shell instead of 3d sub-shell.
(iii) Chromium has configuration `3d^(5)4s^(1)` and not `3d^(4)4s^(2)`.

In potassium, the 19th electron enter into 4s subshells instead of 3d subshells.

Explain why (i) the three electrons present in 2p subshell nitrogen remain unpaired. (ii) in potassium, the 19th electron enters into 4s subshell instead of 3d subshell, (iii) chromium has configuration 3d^(5) 4s^(1) instead of 3d^(4), 4s^2, (iv) the electronic configuration of zinc can be represented as [Ar] 3d^(10) 4s^(2)?

Why does chromium have configuration of type 3d^(5) 4s^(1) instead of 3d^(4) 4s^(2) ?

Number of electrons present in the 3d sub-shell of an element having atomic number 37 is :

The outermost shell electronic configuration 3d^(5), 4s^(2) represents

The outermost shell electronic configuration 3d^(5), 4s^(2) represents

Electronic configuration of copper is 3d^(10)4s^(1) instead of 3d^(9) 4s^(1) .Why?

How many electrons can have s+ ½ in a d-sub-shell?

How many electrons can have s+ ½ in a d-sub-shell?